Differentiate 1.5sqrt x³ - 4/x with respect to x?

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Differentiate 1.5sqrt x³ - 4/x with respect to x?

2007-04-16 14:42:04 · 4 answers · asked by th3one101 2 in Science & Mathematics ➔ Mathematics

4 answers

Let y be 1.5sqrt x³ - 4/x
Therefore y = (3/2)*x^(3/2) - 4*x^(-1)

Differentiate y
= (3/2)*(3/2)*x^(3/2 - 2/2) - 4*(-1)*x^(-2)
= (9/4)*x^(1/2) + 4*x^(-2)
= 2.25*x^(0.5) + 4/(x^2)

2007-04-16 14:50:13 · answer #1 · answered by QiQi 3 · 0⤊ 0⤋

y= 1.5 x(Â³/2) - 4/x

y'= 9/4x^(1/2) + 4 / (x^2)

2007-04-16 21:47:46 · answer #2 · answered by iyiogrenci 6 · 0⤊ 0⤋

d/dx 1.5â(x^3) - 4/x
= d/dx (1.5)x^(3/2) - 4x^(-1)
= (1.5)(3/2)x^(1/2) - 4(-1)x^(-2)
= 2.25 âx + 4/x^2.

2007-04-16 21:46:13 · answer #3 · answered by Scarlet Manuka 7 · 0⤊ 0⤋

4.5x^2 -4/x^2

2007-04-16 21:45:31 · answer #4 · answered by ironduke8159 7 · 0⤊ 1⤋