4x^2 + 7x -2 = 0
is it (4x+2) (x-1)
no, thats not right is it??
2007-04-16 14:32:41 · 8 answers · asked by :) 3 in Science & Mathematics ➔ Mathematics
no (4x+2)(x-1) = 4x^2-2x -2
4x^2 + 7x -2 = (4x-1)(x+2)
Therefore x=1/4,-2
Hope that helps! =)
2007-04-16 14:37:52 · answer #1 · answered by xoxbritz36xox 2 · 0⤊ 3⤋
No, that isn't right.
4x^2 + 7x - 2 = 0
(4x - 1)(x + 2)
2007-04-16 21:37:32 · answer #2 · answered by its_victoria08 6 · 0⤊ 1⤋
Good try, but that would give you 4x^2 - 2x - 2.
If you start with (4x )(x )
Then you would have to find numbers to put in there that would FOIL out to give you your original problem:
(4x-1)(x+2)
2007-04-16 21:39:39 · answer #3 · answered by Anonymous · 0⤊ 1⤋
4x² + 7x -2 = 0
Factorize into (4x + a)(x + b)
so that 4b+a = 7 and ab = -2.
a = -1, b = 2
(4x -1)(x + 2) = 0
x = 1/4 or x = -2
____________________
You can also use the quadratic formula. For a quadratic equation
Ax² + Bx + C = 0
the quadratic formula is:
x = [ -B ± â(B² - 4AC) ] / [2A].
_____________________
Hope this helps.
2007-04-16 21:37:30 · answer #4 · answered by M 6 · 3⤊ 0⤋
4x^2 + 7x -2 = 0
x^2 + 7/4x -2/4 = 0
(x+2)(x-1/4)=0
x1=-2
x2=1/4
2007-04-16 21:38:46 · answer #5 · answered by iyiogrenci 6 · 0⤊ 1⤋
No, when you multiply that back out, you get 4x^2-2x-2.
Try adding a number to both sides of your equation to make the problem easier to break up?
2007-04-16 21:39:04 · answer #6 · answered by SEOP 1 · 0⤊ 1⤋
BIDMAS: brackets, indicies, division, multiply, addition,subtraction...
(4x^2+7x)-2=
(11^2)-2=
(121)-2=
==========119
2007-04-16 21:40:49 · answer #7 · answered by alix_xander 2 · 0⤊ 1⤋
(4x-1)(x+2)
2007-04-16 21:38:45 · answer #8 · answered by dwinbaycity 5 · 0⤊ 1⤋