Here is the math probelm:
Packs of baseball cards are sold in boxes with the same number of packs in each box. Cindy and Eddy each bought full boxes of the packs of baseball cards. Jack bought 200 packs, Cindy bought 250 packs, and Eddy bought 300 packs. What is the greatest number of packs a box could hold?
ok..well I know ya'll are all prolly thinkin 300 is the largest..but.Im not so sure..i think it has to do with LCM (least common multiple) or GCF (greatest common factor).
Please help me out!! i am soo confused.
2007-04-16 14:27:44 · 13 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
i would say it was 50 because thats biggest number that goes into 200, 250 and 300 evenly
2007-04-16 14:31:09 · answer #1 · answered by xoxbritz36xox 2 · 2⤊ 0⤋
GCF is your key here. Not worrying about Jack. Cindy and Eddy bought full boxes . . . so you need the GCF of 250 and 300 which is 50, This will also work for Jack because he has a number with 50 as a factor. Remember is it's the greatest number of packs in a box. Hope this helps you.
2007-04-16 14:41:11 · answer #2 · answered by EEP 1 · 0⤊ 0⤋
Hm. I don't think it has to do with either the LCM or GCF, seems kinda like a logic game. Giving you more information than ya need. I could be wrong, but I do indeed think it's 300 because it says 'Cindy and Eddy each bought FULL boxes of the packs.....'
So, if Eddy bought a full pack and had more than Cindy, then the max, I'd say, would just be 300. *Shrugs*
2007-04-16 14:33:12 · answer #3 · answered by Jedash 1 · 0⤊ 0⤋
You're right... it has to do with the GCF. It can't be 300 because Jack and Cindy bought less than that and they bought FULL boxes! So if we found the GCF ... we would end up with 50. Each box has 50 cards. Jack bought 4 boxes, Cindy bought 5 boxes and Eddy bought 6 boxes. :)
2007-04-16 14:33:51 · answer #4 · answered by Anonymous · 1⤊ 0⤋
The answer is 50 since it is the greatest common factor of 250 and 300 . Jack's number is irrelevant because the information given doesn't specify if he bought full boxes or not.
2007-04-16 14:40:23 · answer #5 · answered by golffan137 3 · 0⤊ 0⤋
It does have to do with their factors.
200 = 2x2x2x5x5
250 = 2x5x7x5
300 = 2x2x3x5x5
the factors tell how many packs could have been in a box, since that is how the packs could be broken up evenly. Circle the numbers that match in ALL THREE sets and then multiply them together to find the GCF.
2007-04-16 14:34:41 · answer #6 · answered by SEOP 1 · 0⤊ 1⤋
50 packs in a box, at most. Any other number will not divide into 200, 250, and 300. You're looking for the GCD (greatest common divisor).
2007-04-16 14:34:09 · answer #7 · answered by morningfoxnorth 6 · 1⤊ 0⤋
The answer is 250. Cindy and Eddy both bought full boxes. Cindy has 250 packs and Eddy has 300 boxes. The both bought a box of 250 packs and then Eddy must have purchased more packs separately. Jack has nothing really to do with this equation.
2007-04-16 14:31:25 · answer #8 · answered by GEE-GEE 5 · 0⤊ 3⤋
They're looking for the largest number that would divide into 200, 250 and 300 with no remainder.
2007-04-16 14:31:51 · answer #9 · answered by Gene 7 · 1⤊ 0⤋
50, I think - all of the numbers (200, 250, and 300) are divisable by 50.
2007-04-16 14:30:51 · answer #10 · answered by scorpion43_db 3 · 1⤊ 0⤋