A curve is defined parametrically by the equations x = t - lnt, y= t + lnt (t>0)?

Question

Find the gradient of the curve at the point where t=2

Answer 1

dy/dx=(dy/dt) / (dx/dt)
=(1+1/t) / (1-1/t)
gradient= (1+1/2)/(1-1/2)

=(3/2 ) / (1/2)
=3