could some one please show me how to work the following problem?

Question

[ 2x^7y^2] ^3
________
4xy^3

the whole problem is in brackets and x^7 is x to the 7th power, etc. could you please work it out or explain how to work it? thanks!

the whole problem except the outside 3.

i don't understand where you all are getting the 8 in the 1st step

Answer 1

****I added how to get the 8 in the first step****

you distribute the ^3 through the top and get 8x^21y^6/4xy^3
because an exponent raised to an exponent means to multiply the exponents

***** 2*2=4*2=8=2^3********

8/4=2 x^21/x=x^20 y^6/y^3=y^3

2x^20y^3 is the final answer.

Hope that helps!

Answer 2

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Answer 3

[ 2x^7y^2] ^3
________
4xy^3


=(8x^21 y^6 ) / (4xy^3)

=2 x^20 y^3

Answer 4

first multiply the cube
8x^21*y^6(i hope it's 2x^7multiply by y^2)
over
4xy^3
divide
2x^20y^3y