solve the equation. express radicals in simplest form?

Question

b^2+4/5b+-1/5

3n^2=-10n-2

Answer 1

b^2+4/5b+1/5=0
5b^2+4b+1=0
no real roots

b^2+4/5b-1/5=0
5b^2+4b-1=0
b1=-5/8

b2=1/8

Hint: use quadratic formula

3n^2=-10n-2

3n^2+10n+2=0
n1=(-5-sqrt(19))/3
n2=(-5+sqrt(19))/3