Math Help: (x-5)^2=6?

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I need some help- last problem and I can't remember how to do it:
(x-5)^2=6

+/-41
+/-sqrt41
-5+/-sqrt6
5+/-sqrt6

2007-04-16 13:36:18 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics

Take the square root of each side of the equation to get:

x-5 = ±√6

add 5 to both sides
x = 5±√6

2007-04-16 13:40:08 · answer #1 · answered by Kathleen K 7 · 0⤊ 0⤋

Start by:
Square rooting both sides leaving you with -
x - 5 = +/- sqrt[ 6 ]
Add 5.
x = 5 +/- sqrt[ 6 ]

2007-04-16 20:40:58 · answer #2 · answered by cbagan89 2 · 0⤊ 0⤋

(x-5)^2=6

x-5=+ - sqrt 6
x=5 +/- sqrt 6)

5+/-sqrt6 is the answer

2007-04-16 20:41:43 · answer #3 · answered by iyiogrenci 6 · 0⤊ 0⤋

Take sq rt

x - 5 = + - sq rt 6

x = 5 + - sq rt 6

2007-04-16 20:38:27 · answer #4 · answered by richardwptljc 6 · 0⤊ 0⤋