please solve.................... (radicals)?

Question

1.) (4+radical 3)+(1-radical 2) =

2.) radical 5 (6-radical 15) =

3.) radical 3 (radical 3+2)^2 =


* i'll give points for the first person with the right answers, if not i'll give for trying hard, too. help.....................!!!!!!!!!!!

Answer 1

1.) (4+radical 3)+(1-radical 2) =
4+sqrt3+1-sqrt2 = 5 +sqrt3 - sqrt2

2.) radical 5 (6-radical 15) =
sqrt5(6-sqrt15) =
6sqrt5 - (sqrt 5)(sqrt 15)=
6sqrt5 - (sqrt 5)(sqrt5)(sqrt3)
6sqrt5 -5sqrt3

3.) radical 3 (radical 3+2)^2 =
sqrt3(sqrt3+2)^2=
sqrt3(3+4sqrt3+4)=
3sqrt3 +4sqrt3(sqrt3) +4sqrt3=
7sqrt3+12

Answer 2

(4 + √3) + (1 - √2)
5 + √3 - √2

Answer 3

1)
(4+radical 3)+(1-radical 2)
=4-4 radical 2 +radical 3 -radical 6

2)
radical 5 (6-radical 15)
=6 radical 5 - 5 radical 3

3)
radical 3 (radical 3+2)^2
= radical 3 ( 3+4+2 radical 3)
=6 + 7 radical 3