Factor the following trinomial (plz help, easy ten pts to correct answer)?

Question

k so im usualy rly good at math. but i cant figure this one out. plz show ur work! thank you

10k³ + 25k - 35k²

Answer 1

10k³ + 25k - 35k²=0
arrange the constants in order of decreasing powers:
10k^3 -35k^2+25k=0
factor out 5k:
5k(2k^2-7k+5)=0
5k(2k-5)(k-1)=0
solving:
5k =0 ====>k=0
2k-5=0 =====> k = 5/2
k-1 =0 =====> k=1

Answer 2

First arrange the terms in descending order of the powers of k:

10k³ + 25k - 35k² = 10k³ - 35k² + 25k

Then take out the greatest common factor, 5k:

10k³ + 25k - 35k² = 10k³ - 35k² + 25k = 5k (2k² - 7k + 5)

Now factor (2k² - 7k + 5) into (2k + a)(k + b) so that
a+2b = -7 and ab = 5:

5k (2k² - 7k + 5) = 5k(2k - 5)(k - 1)

Hope this helps!

Answer 3

10k^3 + 25k - 35k^2

Since you have a k in each term, factor out a k first (and some coefficients) and you can then factor a quadratic which is far easier.

5k(2k^2 - 7k + 5)

5k(2k - 5)(k - 1)

Answer 4

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Answer 5

10k³ + 25k - 35k²

=5k (2 k^2- 7k +5)

=5k (k-1) (k-5/2)

Answer 6

we can factor out a 5k from all 3 terms:

5k(2k^2 + 5 - 7k) = 5k(2k^2 - 7k + 5)
= 5k(2k - 5)(k - 1)