ok well i need help .......wiht htis problem x2= 8x-16...................the x2 mean x to the second power
2007-04-16 12:58:32 · 7 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
a would be 1 b would be 8 and c would be -16
you do -b plus or minus the sq. root of b2 - 4ac over 2a. Complete the equation you will get two answers.
2007-04-16 13:08:09 · answer #1 · answered by chrisdaniel3651 2 · 0⤊ 0⤋
x2= 8x-16
subtract 8x and add 16 for both sides to set the equation equal to 0
x^2 - 8x + 16 = 0
to factor, look for two number that multiply to 16 and add to -8.
the two numbers are -4 and -4
(x-4) (x-4) = 0
or (x-4)^2 = 0
x = 4
2007-04-16 20:03:41 · answer #2 · answered by 7 · 0⤊ 0⤋
I suppose you need to find the roots (or the zeros) of x?
x^2 = 8x - 16
x^2 - 8x + 16 = 0
(x - 4)(x - 4) = 0
(x - 4)^2 = 0
x = 4
2007-04-16 20:01:49 · answer #3 · answered by Bhajun Singh 4 · 0⤊ 1⤋
Answer is -8.
1. Divide both sides by x.
2. Then subtract 16 from 8.
3. Answer.
1. (x2)/x= (8x-16)/x: x=8- 16
2. x=8 -16 : x= -8
2007-04-16 20:07:25 · answer #4 · answered by ICYCUBE 2 · 0⤊ 0⤋
First you need to set it equal to zero.
0 = x^2 - 8x +16
find a common factor
0 = (x - 4)(x-4)
set each part equal to zero and solve
x = 4
2007-04-16 20:04:31 · answer #5 · answered by Karissa 3 · 0⤊ 0⤋
^2 means to the second power
get everything to one side
x^2-8x+16=0
=(x-4)(x-4)=0
x-4=0
x=4
2007-04-16 20:04:26 · answer #6 · answered by dla68 4 · 0⤊ 0⤋
x^2= 8x-16
x^2-8x-16=0
(x-4)^2=0
x-4=0
x1=x2=4
2007-04-16 20:05:36 · answer #7 · answered by iyiogrenci 6 · 0⤊ 0⤋