How many milliliters (mL) of water must be added to 30mL of a 6.0M solution to obtain a 0.25M solution?

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2007-04-16 11:58:52 · 2 answers · asked by t_mack_33 2 in Science & Mathematics ➔ Chemistry

M1V1 = M2V2
(6.0M)(30mL) = (0.25M)(V2)
V2 = 720 mL
720 mL total solution- 30 mL starting solution = 690 mL added

2007-04-16 12:04:06 · answer #1 · answered by moneymonty 3 · 0⤊ 0⤋

(30 x 6/0.25) - 30

2007-04-16 19:03:10 · answer #2 · answered by Gervald F 7 · 0⤊ 0⤋