Why does 3n^2+9n+6 have more than one factored form while the other quadratics only have one possible answer?
2007-04-16 11:27:44 · 2 answers · asked by andrew 3 in Education & Reference ➔ Homework Help
It has more than one factored form .
1. (3n+6)(n+1)=0
2. 3(n^2+3n+2)=0
3(n+1)(n+2)=0
It had essentially the same equation because the second one is not fully factored and you will arrive at the same answer for n.
2007-04-16 11:49:23 · answer #1 · answered by Dave aka Spider Monkey 7 · 0⤊ 0⤋
The two factored forms are 3(n^2+3n+2) and (3n+6)(n+1). The first equation is not considered fully factored since you can still factor what is in the perentheses, once you do that you will distribute the 3 and end up with the same thing as the second equation. Oh and remember when factoring everything's set = to zero.
2007-04-16 18:35:48 · answer #2 · answered by Anonymous · 0⤊ 0⤋