Homework help please?

Question

Find the equation, in slope-intercept form, of the line that passes through the points
(-5, 2) and (-4, 1).

Answer 1

slope formula

m = y₂- y₁/ x₂- x₁

m = 1 - 2 / - 4 - (- 5)

m = - 1 / - 4 + 5

m = - 1 / 1

m = - 1

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Slope intercept formula

y = mx + b

2 = - 1((- 5) + b

2 = - (- 5) + b

2 = 5 + b

2 - 5 = 4 + b - 5

- 3 = b

- - - - - -

The equation

y = - x - 3

- - - - - - - s-

Answer 2

The answer is y = -x - 3 (Slope-intercept form) or x + y + 3 = 0.

This can be solved by:-

Let y = m*x + c, in the Slope-intercept form, be the equation of the line passing through the points A(x1,y1) = (-5,2) & B(x2,y2) = (-4,1). Here m & c are constants which can be found out.

m = (y2 - y1) / (x2 - x1)
m = (1 - 2) / (-4 + 5)
m = -1 / 1
m = -1

Putting A(-5,2) in the equation y = -x + c, to find c.
2 = -(-5) + c
c = 2-5
c = -3

So, the final equation is y = -x - 3 (Slope-intercept form), passing through the points (-5,2) & (-4,1).

Answer 3

The slope would be:

m = (2-1)/(-5 - -4) = -1

the general slope intercept form equation is:

y = mx + b

substitute m, you get:

y = -x + b

Substituting the first point and solving for b you get:

2 = -(-5) + b
b = -3

The final equation would be:

y = -x - 3

Answer 4

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