For a 4-digit number, let a, b, c, and d be the digits, so we get: 9*(1000*a+100*b+10*c+d) = 1000*d + 100*c + 10*b + a
Simplifying: 8999*a + 890*b = 10*c + 991*d
This implies that d = 10 - a, by looking at the last digits, which we substitute, and get: 9990*a + 890*b = 10*c + 9910
When we divide by 10, we get 999*a + 89*b = c + 991
This implies that a = 1, so 89*b = c - 8
This implies that b = 0 and c = 8, and there is only one solution: 9*1089 = 9801.
2007-04-16 11:19:26
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answer #1
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answered by dboy 3
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France, I would bet my monitor that your mother DID NOT write this. What exactly is "the same result"? If you wanted the product of something x 9 to get 8712, something will not be a 4-digit number.
Let's be more honest, and at the same time, use the English more correctly.
2007-04-16 18:20:04
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answer #2
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answered by cattbarf 7
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there is no possible way. what grade is your daughter in because i am in advanced 6th math and my teacher could not answer that question
2007-04-16 18:23:55
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answer #3
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answered by Lizbef 2
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it would be cheating to help you. im really sorry. im tempted to ask for help on my school work all the time, but that is entirely unfair. if she passes b/c i helped her, she doesnt deserve to pass, if she passes b/c she figured out all the answers, shes fine. but really, dont ask for people to do the work for you.
2007-04-16 18:17:49
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answer #4
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answered by Kari 2
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1111?
seems possibly simple enough to me hehe
2007-04-16 18:18:39
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answer #5
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answered by Anonymous
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No fooling
2007-04-16 18:17:38
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answer #6
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answered by Sugar 7
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wish i could help but sorry i don't know.
2007-04-16 18:17:04
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answer #7
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answered by chanel 2
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tell her to do her own homework
2007-04-16 18:17:55
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answer #8
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answered by Anonymous
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i can help, but in which grad she is?
2007-04-16 18:24:15
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answer #9
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answered by wtf_for_you 1
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wish i could help
but i dont know wat your talking about
2007-04-16 18:18:04
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answer #10
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answered by ?.:mystery man:.? 1
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