given y= 1/3x^2+1/2x^2-6x+8 what are the critical points?

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given y= 1/3x^2+1/2x^2-6x+8 what are the critical points?

2007-04-16 09:36:11 · 3 answers · asked by Patricia m 1 in Science & Mathematics ➔ Mathematics

3 answers

Set the derivative equal to zero and solve for x. This will give you the critical points. (maximums and minimums)

2007-04-16 09:40:37 · answer #1 · answered by Jeffrey K 7 · 0⤊ 0⤋

What ozo wrote is correct, and it's easy to calculate, so I recommend you not let others give you the final answer. Once you have the most important info needed to solve a problem it really is important to do it yourself so that you learn the method well.

Best of luck.

2007-04-16 16:42:37 · answer #2 · answered by rasraster 2 · 1⤊ 0⤋

where dy/dx=0

2007-04-16 16:38:43 · answer #3 · answered by Anonymous · 1⤊ 0⤋