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Calculate the number of moles of NO3- ions in 3.20 L of 0.220 M Mg(NO3)2?

2007-04-16 09:27:32 · 2 answers · asked by charobs 1 in Science & Mathematics ➔ Chemistry

2 answers

0.220 mol/L Mg(NO3)2 x 3.20 L = 0.704 mol Mg(NO3)2
0.704 mol Mg(NO3)2 x 2 mol NO3/mol MG(NO3)2 =
1.41 moles NO3

2007-04-16 09:40:52 · answer #1 · answered by moneymonty 3 · 0⤊ 0⤋

3.2 x 2 x 0.22

2007-04-16 16:31:59 · answer #2 · answered by Gervald F 7 · 0⤊ 0⤋

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