Half life problem- Help!?

Question

The half-life of carbon-14 is 5730 years. The daughter is stable nitrogen-14. A sample contains 1/4 C-14 and 3/4 N-14.

How OLD is the sample?

Please show as much detail as possible to show me how this works. Formula's ect.
Thanks

Answer 1

starting with 100% C.
after 5730 years, you drop to 50% C and 50% N
after another 5730 years, you have 25% C and 75% N.

The sample is 11460 years old.

Answer 2

Half of carbon decays into a new element (nitrogen) in an organism or item after 5730 years. Since 1/2 of 1/2 is 1/4, the carbon has gone through two half lives. 5730x2=11460 years. The sample is approximately 11460 years old.

Answer 3

0= 160 g. 1= 80 g 2= 40 g. There are 2 half-lives, because 11,460 divided by 5,730 equals 2, which means 2-half lives. very simple.

Answer 4

1/4 C-14 is what's left after 2 half-lives or 11,460 years.

Answer 5

A half-life is the amount of time taken for half the atoms initially present to decay.

After one half-life, you have half.

After two half-lives you have half again = 0.5 * 0.5 or 0.25

You know that 0.25 of what's left is C-14, therefore two half-lives have elapsed or 11,460 years

Answer 6

well carbon turns into half, then another half, so its 1/4, which takes 5730x2 or 11460 years

Answer 7

1867

Answer 8

http://en.wikipedia.org/wiki/Radiocarbon_dating
Go to the following section of the article .. "Computation of ages and dates"
All the formulas and explaination can be found there.
Nope.. not gonna do it for ya, sorry :)

Answer 9

5730
- 14
------------
4330

43.30