X^2+4y^2=16?

Question

Convert the equation to polar form.

Answer 1

x=rcos(v)
y=rsin(v)
r^2cos^2(v)+4r^2sin^2(v)=16
is the same as 3r^2sin^2(v) +r^2=16
is the same as r^2(3sin^2(v)+1)=16