Find the velocity for the tip of the hour hand of a clock, if the hand is 27ft. long.?

Answer 1

Since we know the radius of the clock face (27 feet or 324 inches) we can determine the circumference as being (r*2)*3.1415, or pi, resulting in an answer of 2035.692 inches. Since the tip of the hand makes one circle of the clock face every twelve hours, that leaves us with a velocity of 169.641 inches per hour.

Answer 2

Perimeter of tip of hand movement for 12 hours is 2*pi*r = 54pi ft

velocity = distance/time

= 54pi / 12 hours
12 hours = 12 * 60 mins * 60 secs = 43200 seconds

So velocity = 54pi / 43200 feet per second.
Or 0.00393 feet per second

Answer 3

27 ft=radius
(27*2)=diameter
(54*pi)=circumference of the circle
so...
the hand travels 169.646 feet every twelve hours or...
14.1372 feet per hour
While other have this answer, this is only the speed, velocity also requires direction, so the answer is
14.1372 feet/hour FORWARD

Answer 4

C = 2π x 27 ft = 54π ft
T = 3600 sec
V = C / T
V = 54π / 3600 ft / sec
V = 0.565 ft / sec