Solving Square Root Problem?

Question

Having trouble. Can someone please SHOW me how this problem is done. I'd like to be able to understand how its solved. Much thanks. √meaning Sq. Root

[ √3 + √2 + √1 ] ^4

Answer 1

ok anything that is a square root raised the square so square root of s ^2 is just 2. so to the 4 is going to make it like 2^2. so try it out now and if you still don't understand just ask away

Answer 2

When you have an exponent, it means you take whatever the base is and multiply it by itself that number of times.

If you had w^4 that would be WxWxWxW, for example.

So IF you had (sqrt 3) ^4, that would end up being 9 (ask if you need know why).

But your problem is a bit more complicated and necessitates use of distributive property... though I suppose you could get an APPROXIMATION for the base number first...

but you will need to take:
(sqrt3 + sqrt 2 + 1) x (sqrt3 + sqrt 2 + 1) x (sqrt3 + sqrt 2 + 1) x (sqrt3 + sqrt 2 + 1)

Look at:
(x + y + z) ^2 =
x^2 + 2xy + 2xz + y^2 + 2yz + z^2

then keep applying distributive property like that. Does that make sense?

Answer 3

i became into in a position to sparkling up via inspection: x = 5. The sq. root of x + 4 is sqrt(9) = 3. The sq. root of x - 4 is sqrt(a million) = a million. the version is two. i seen it as, "What 2 sq. numbers variety via 8 and function sq. roots that variety via 2?" i understand that 2 consecutive sq. numbers variety via a wierd variety equivalent to a minimum of one extra advantageous than two times the sq. root of the smaller sq.. 8 is comparable to 3 + 5, making it the sum of consecutive odd numbers. this ability that the 1st sq. may be the sq. of one 0.5 of one below the 1st odd variety. ((3 - a million) / 2)^2 = a million, so the 1st sq. is a million and the 2nd, 8 bigger, is 9. fixing the two x - 4 = a million or x + 4 = 9 provides us x = 5.

Answer 4

let √3 + √2=x

(x + 1 ) ^4 =?

Answer 5

sqrt 3 =1.732
sqrt 2 =1.414
sqrt 1 =1.000
sum = 4.146

sum^4 = 295.47