For the reaction:
NH3 + O2 → NO + H2O
34.06 g of NH3 are completely reacted with an excess of the other reactant.
If the percent yield is found to be 90.66 %, how many grams of H2O are actually produced ?
2007-04-16 07:02:18 · 3 answers · asked by sleepthei 3 in Science & Mathematics ➔ Chemistry
You should balance the equation first..
4 NH3 + 5 O2 ==> 4 NO + 6 H2O
2007-04-16 07:13:38 · answer #1 · answered by Eric 6 · 1⤊ 1⤋
34.06 grams of NH3 = 34.06 grams/17.03grams/mol = 2 mol NH3
molar ratio of NH3 reacted : H2O Produced = 1:1 so if 2 mol NH3 reacted, 2 mol water were produced.
therefore,
2 mol H2O * 18.0153g/mol = 36.0306g H2O
since percent yield was 90.66 % , grams H2O actually produced
= 36.0306 * 90.66/100 = 32.66534196 grams of water
~ 32.7 grams of water were actually produced.
2007-04-16 07:13:06 · answer #2 · answered by NArchy 3 · 0⤊ 0⤋
The first answer 32.4 is correct
2007-04-16 07:23:09 · answer #3 · answered by maussy 7 · 0⤊ 0⤋