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a) en stands for ethylenediaminetetraacetate , a hexadentate ligand ion
b) The subscript f in Kf stands for formation
c) A very large value of Kf for a chemical reaction in which a coordination complex is a product would indicate that the complex formed is a relatively stable one
d) A very large value of Kf for a chemical reaction in which a coordination complex is a product would indicate a relatively small decrease in Gibbs free energy

use the below information:
*polydentate ligands result in more stable complex ions
then do monodentate ligands
An example of formation equilibrium for a complex ion in solution is:

Al3+ + 6F− ↔ [AlF6]3− Kf = 5.0 × 10−3

ΔG = −RT ln( Kf )
remember, the more negative the value the of ΔG the more stable are the products of reaction that are formed

2007-04-16 06:26:04 · 3 answers · asked by Anonymous in Science & Mathematics Chemistry

3 answers

b and c are true.

2007-04-16 06:29:48 · answer #1 · answered by Gervald F 7 · 0 0

1) en stands for ethylenediaminetetraacetate , but it is not a hexadentate but a tridentate ligand.

2) f is Kf stands for forward and not formation.

3) Kf being large would mean that the concentration of the product (the complex) will be greater at equilibrium.

4) Change in free energy will be large for large values of Kf

2007-04-16 07:15:16 · answer #2 · answered by Anonymous · 0 0

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2016-11-24 22:41:58 · answer #3 · answered by Anonymous · 0 0

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