PLEASE HELp!!!!!!!!!!!!! math problems?

Question

a.) Explain why solving (x - 4) (x-7) = 6 by setting each factor equal to 6 is not correct.

b.) Determine the correct solution to (x-4) (x-7) = 6

Answer 1

a) It isn't correct because if you did that, you would get 10 and 13. Checking 10 into the original equation, you get 6*3=6, which is false. Checking 13, you get 9*6=6, also false. You need to get zero on one side before factoring.

b)
x^2 - 11x + 28 = 6
x^2 - 11x + 22 = 0

Using the quadratic formula;
x = [11 +/- sqrt(121-4*1*22)]\2 = [11 +/- sqrt(33)]/2

Answer 2

for b)

(x-4)=6

add 4 on both sides
x=10

x-7=6
add 7 on both sides
x=13