(3-2)^2=(3-4)^2 then 3=2 is it right?

Answer 1

THat's my great philosopher!

Answer 2

First off, you must mean 2=4.

Secondly, the statement proves nothing about 2 or 4 or 3.

(3-2)^2 = (3-4)^2

(1)^2= (-1)^2

1 = -1

Of course, saying 1 = -1 would also be false, because the sequence overlooks the fact that the square root of x^2 = -x or x - it has two possible answers; not a single unique answer.

You could just as well say that 150 degrees = 30 degrees, since the sine of both angles is 0.5.

Answer 3

I see your point. Often in math texts, they use the example of the reflexive property of equality this way:

x + 2 = 5 and 3 + 2 = 5, so x must equal 3. So, every statement must equal itself.

But just because two statements are equal, doesn't mean they are the same statement! That's an error in logic that philosophers categorized long ago. A class in logic would be a good place for a budding philosopher like yourself!!

Keep asking questions!!

Answer 4

(3-2)^2=(3-4)^2 then 3=2 is it right ? False

the equation is right
1^2=-1^2
1=1

Answer 5

(3-2)^2 = (3-4)^2, then 3=2 (?) -------> NO.

[x-(x-1)]^2 = [(x-(x+1]^2,

[0-1]^2 = [0+1]^2

(-1)^2 = (+1)^2

1 = 1, not -1 = 1

Answer 6

No;
this won't cause a false statement.

3-2 is 1, 3-4 is -1, both are 1 when squared:

1 = 1

Answer 7

No because x^2 = (-x)^2 but x and -x are not same

that means a^2 = b^2 means a= b or a = -b

Answer 8

3 can never equal 2.

Answer 9

No, because when you have a^2 = b^2 and take the square root of both sides, you don't necessarily get a=b. You get ±a = ±b, or rather just a = ±b.

Answer 10

The first statement is true. The second statement is false.