give me the answer of this X^2+2X+1=0?

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Answer 1

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Solve for the "x" variable in the equation....

x^2 + 2x + 1 = 0

First: multiply the 1st & 3rd term to get 1. find two numbers that give you 1 when multiplied & 2 (2nd term) when added/subtracted. the numbers are (1 & 1). rewrite the expression with the new middle terms.

x^2 + 1x + 1x + 1 = 0

Sec: with 4 terms - group "like" terms & factor both sets of parenthesis.

(x^2 + 1x) + (1x + 1) = 0

x(x + 1) + 1(x + 1) = 0

(x + 1)(x + 1) = 0

(x+1)^2 = 0

Third: eliminate the exponent - find the square root fo both sides.

V`(x+1)^2 = V`(0)

V`(x+1)(x+1) = V`(0)

x + 1 = 0

*Solve for "x" - subtract 1 from both sides (when you move a term to the opposite side, always use the opposite sign).

x + 1 - 1 = 0 - 1

x = 0 - 1

x = -1

Answer 2

(x+1)^2=0 x=-1