Can i have some help with this equation?

Question

Oxalic acid + Sodium Hydroxide ==>
H2C2O4 + NaOH ==>
I dont know what products are formed, or even what they are called.
Should there be 2 mols of NaOH?
=S

Answer 1

Mikee above has it mostly correct. If there is excess sodium hydroxide, and the reaction proceeds to completion, then he is correct:

H2C2O4 + 2NaOH ===> Na2C2O4 + 2 H2O

However, if there is an excess of oxalic acid, then the reaction will have a mixture of the monobasic (HNaC2O4) and dibasic (Na2C2O4) oxalate salt.

But Sodium oxalate (Na2C2O4) will be the major product, because excess sodium hydroxide is more than strong enough to deprotonate both acid groups, even though the two pKa values are 1.25 for the first deprotonation, and 3.81 for the second.

Answer 2

You have oxalic acid , it has two carboxyl groups , the most simple di-oic acid so it will take two NaOH per oxalic acid.
H2C2O4 + 2NaOH ==> NA2C2O4 + 2H20
Sodium oxalate is the product