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What work is done when 5.0 C is moved through an electric potential difference of 1.5 V?

2007-04-16 03:25:15 · 4 answers · asked by Jeff D 1 in Science & Mathematics Physics

4 answers

Work done= VIt
= V* amount of charges
= 1.5V * 5.0 C
= 7.5 J of work done

V=voltage
I= current
t= time
It= amount of charges (coulombs(C)

2007-04-16 03:32:14 · answer #1 · answered by Anonymous · 0 0

By definition on electric potential the work done is W = qV Thus W = 5.0C x 1.5 V = 7.5 Joule

2007-04-16 10:33:16 · answer #2 · answered by physicist 4 · 0 0

ΔV = -W/q

W = -qΔV

W = -(5.0 C)(1.5 V)

W = -7.5 J

2007-04-16 10:32:30 · answer #3 · answered by Bhajun Singh 4 · 0 0

7.5 Joules.

HTH

Doug

2007-04-16 10:32:05 · answer #4 · answered by doug_donaghue 7 · 0 1

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