factorise 2^2-35x+98
2007-04-16 02:18:40 · 5 answers · asked by jenny 1 in Science & Mathematics ➔ Mathematics
I answered this question before but i will explain more in depth
is assume 2² = 2x²
2x² - 35x + 98 = 0
The middle term is - 35x
Find the sum of the middle term
multiply the first term 2 bythe last term 98 equals 196 and factor
The factors of 196 =
1 = 196
2 x 98
4 x 49
7 x 28 . . .<=. .use these factors
14 x 14
- 28 and - 7 satisfy the sum of the middle term
insert - 28x and - 7x into the euation
2x² - 35x + 98 = 0
2x² - 28x - 7x + 98 = 0
2x(x - 14) - 7(x - 14) = 0
(2x - 7)(x - 14) = 0
- - - - - - - -s-
2007-04-16 03:17:23 · answer #1 · answered by SAMUEL D 7 · 0⤊ 0⤋
I think you mean
2x^2-35x+98
product = 2* 98
sum = -35
so we get -28 and -7
now 2x^2-35 x+ 98
= 2x^2-28 x- 7x +98
= = 2x(x-14) - 7(x-14)
= (x-14)(2x-7)
2007-04-16 09:25:37 · answer #2 · answered by Mein Hoon Na 7 · 0⤊ 0⤋
4-35x+98
2007-04-16 09:26:28 · answer #3 · answered by VISHAAL J 1 · 0⤊ 0⤋
=(2*2)-(35*{+98})
=(4) - (3430)
= -3426
+98 = 98
2007-04-16 09:28:08 · answer #4 · answered by KAY 1 · 0⤊ 0⤋
(2x-7)(x-14)=0
2x=7 x=7/2
x-14=0 x=14
2007-04-16 10:36:52 · answer #5 · answered by Dave aka Spider Monkey 7 · 0⤊ 0⤋