How many grams are there in 0.5 equivalents of Ca+2 and K+1?

Question

I know that an equivalent is equal to the absolute value of the ionic charge. I also know that there are 2 eq in 1 mole of Ca+2. That being said, 1 eq of Ca+2 should be 0.5 moles, right? If thats true, then 0.5 eq should be 0.25 moles. If I have 0.5 equivalents of Ca+2 @ 40.1 amu per mole, then would the answer be 10.025 grams? Using that train of thought, 2 equivalents of K+1 with a amu of 39.1 would be 78.2 grams ( 1 eq K+1 per mole @ 39.1 amu per mole). Am I right?

Answer 1

1 mole Ca+2 = 2 Equivalents . The mass is 40.1grams
So 0.5 Eq = 40.1/4 = 10.025g . Your answer is right

For K+1 as K is monovalent 1 Eq = 1 mole =39.1g and 2 Eq = 2*39.1 = 78.2g

Correct