if . . . h(i,j,k)= h(1,2,3)= i+4(i-j) power of 2 +2(j-k)power of 3 = 3 . . . . . how do u work it out?

Question

i have been tryin 2 figure out this question for an our and a half n it s NOT funny! . . . . . please help! n it function notation if u were wondering

Answer 1

i=1
j=2
k=3

h(i,j,k)= h(1,2,3)
= i+4(i-j)
=1+4(1-2)
=-3
power of
2 +2(j-k)

=(-3)^ 0


=1

Hint:
the other all power doesn't necessary to calculate
because any power of 1 gives 1 except infinity.

Answer 2

1