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7 answers

what measurements have you so far, theres prob no formula just work it out

2007-04-15 22:30:13 · answer #1 · answered by mrs r 2 · 0 0

Sorry i cannot really answer this question bcoz any type of triangle can be drawn inside the square. However i assume you mean that the triangle has a base equal to one side of the square and its two other lengths touch the other side of the square. After working out the equations, I get perimeter= y + 2[sqrt(5 ysquare/4)]. The y is the length of one side of the square. The 2[sqrt(5 ysquare/4)] is found by using pythagoras theorem. So what do you say?? With only the lenght of one side of the square i can find the perimeter of the triangle. But you can have other triangles. that one i assumed it as explained above. Hope it helps...

2007-04-16 12:39:51 · answer #2 · answered by Y L 2 · 0 0

If you draw a diagnol from one vertex non joining vertex at the opposite side of the square, forming a triangle.

The sum of the sides of the triangle is the perimeter.

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2007-04-16 08:50:11 · answer #3 · answered by SAMUEL D 7 · 0 0

You need to look at each of the three sides and work the lengths out one at a time. Add the lengths of the three sides to give you the perimeter.

You haven't given enough information for anyone to solve the problem.

2007-04-16 05:36:28 · answer #4 · answered by jansahar 3 · 0 0

It depends. There are lots of ways of drawing a triangle within a square.

2007-04-16 05:49:19 · answer #5 · answered by Anonymous · 0 0

A figure is required.

2007-04-16 05:37:59 · answer #6 · answered by iyiogrenci 6 · 0 0

We can't help you as there are no figures defined. Sorry :(

2007-04-16 09:24:53 · answer #7 · answered by sweet_angel92 3 · 0 0

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