Hi I have a probability question. And it can be related to Poker (cause thats what I need it for =). My question is ...
I have 1100 chips and my opponent has 1900 chips. We are all-in and my odds of winning the pot (doubling up) was 81%. I win.
In the same game, my opponent has 750 chips left and I have 2250 chips. We are all-in again and I am 67% to take the rest of his chips. BUT instead, HE wins and doubles up thereby we now have 1500 chips each.
We go all-in again and I am 61% to win and I do and I win the tournament. The question is ... WHAT WERE MY OVERALL ODDS OF WINNING THAT GAME? I was 81% to double up then I was 67% to win the game (but lost), then I was 61% to win the game (and won).
What is the equation you use to figure this out?? Would there be any variation if the stack sizes above were different? (Supposing I had 1400 chips on the last all-in and won and he was left with 200 chips, how would that affect the outcome?).
Thanks so much for info !!!!!
2007-04-15
21:17:04
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5 answers
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asked by
Ertai2
4
in
Science & Mathematics
➔ Mathematics