Chemistry - calculating concentration?

Question

I don't understand how to work the following out. Could someone please give me either a formula or process for calculating these concentrations. I don't necessarily want the answers because I won't learn anything that way, but I don't understand how to figure it out!


You have a solution containing 13.6 mg/ml of the protein Bovine Serum Albumin (BSA). Molar weight of BSA is 68, 000 Da (Daltons).

What is the concentration of this solution in:

________g/L (grams/liter)
________M (moles)
________mM (millimoles)
________uM (micromoles)

How many millimoles of BSA are present in 1ml of this solution?

Answer 1

13.6*10^-3 g / 10^-3 L = 13.6 g/L
M = 13.6*10^-3g / 68,000
mM = 13.6/68,000
µM = 13.6/68

Answer 2

Assume that the consentration is "A"mg/ml
*Amg/ml x 1g/1000mg x 1000ml/1L = A g/L
*I think that you mean mol/L( in expressing concentration, M indicates Molarity)
Assume that concentration is "A"mg/ml & "M" is the molar weight of the material, so:
Amg/ml x 1mol/Mg x 1g/1000mg x 1000ml/1L = B M (or mol/L) B=A/M
*B mol/L x 1000mmol/1mol = C mM (or mmol/L & C=1000B)
*B mol/L x 10^6umol/1mol = D uM (or umol/L & D=10^6xB)
GOOD LUCK!

Answer 3

ok its 13.6grams/litre... since u actualy convert mg to g and ml to l... erm change daltons to mole.. check your conversion table.. millimoles to moles is X1000 and micromoles to moles is 10^6 i think...everything is in your conversion table... check it out!