2007-04-15 20:34:10 · 11 answers · asked by Yñkhez 4 in Science & Mathematics ➔ Mathematics
Technically I don't think so, I believe that it's impossible. Even in a modular system that couldn't happen, logically.
There you go. I'm glad I could help. :)
2007-04-16 04:02:46 · answer #1 · answered by iamanicecaringfriend 3 · 0⤊ 1⤋
Yes, 10 +10=100 in base 2 or binary math
10
+ 10
---------
100
2007-04-16 11:20:13 · answer #2 · answered by Dave aka Spider Monkey 7 · 0⤊ 0⤋
Yes - if you're using binary. The binary numbers go:
0 = 000
1 = 001
2 = 010
3 = 011
4 = 100 etc.
Therefore, 10+10=100 is the same as 2+2=4 in binary.
2007-04-16 03:41:39 · answer #3 · answered by anonymous 2 · 2⤊ 0⤋
Not in normal arithmetic. It may be 10 X 10 and if the multiplication symbol is handwritten, may be wrongly read as a +
2007-04-16 03:42:44 · answer #4 · answered by Swamy 7 · 0⤊ 0⤋
Not in decimal values(with base 10).it is possible only in binary mode..in which 0+0=0,1+1=0(with carry 1),1+0=1
so 10
10
-----------------------
10 0
2007-04-16 04:54:26 · answer #5 · answered by kapil Dev 1 · 0⤊ 0⤋
emm... in my opinion 10+10 can 100 if its been add many time.. but if it just 10+10.. of course it cannot be 100 n one more answer... in base 2... of course
2007-04-16 03:49:19 · answer #6 · answered by Anonymous · 0⤊ 1⤋
Yes - in base 2.
2007-04-16 03:36:46 · answer #7 · answered by blighmaster 3 · 2⤊ 0⤋
Yes in Binary (base 2) Arithmetic
4----2----1
------1---0
------1---0
1----0---0
Read as 1 two plus 1 two = 1 four and zero twos.
2007-04-16 04:25:31 · answer #8 · answered by Como 7 · 0⤊ 0⤋
Looks like the math folks have told the turth well done grass hoppers. And you too crickets
2007-04-16 04:35:25 · answer #9 · answered by Anonymous · 0⤊ 0⤋
Yes, in base 2 (binary) and logarithms.
2007-04-16 03:48:39 · answer #10 · answered by Anonymous · 1⤊ 0⤋