Algebra Question?

Question

How does this:

3*((1-(1/2)^n)/1-(1/2))

become this:

6*(1-(1/2)^n)

Thankyou, I have a test tommorrow.

Answer 1

Since the denominator is 1-1/2 which equals 1/2 after multiplying the top and bottom by 2, you get rid of the 1/2 in the denominator and get the 6 in the numerator.

Answer 2

I think you have your parentheses a little wrong. I think you mean

3*((1-(1/2)^n)/(1-(1/2)))

Let's rewrite that for clarity.

3* {[1-(1/2)^n] / [1-(1/2)]}

Simplify the denominator.
1 - 1/2 = 1/2

3* {[1-(1/2)^n] / [1-(1/2)]}

= 3* {[1-(1/2)^n] / [1/2]}

= 2*3*[1-(1/2)^n]

= 6*[1-(1/2)^n]

Answer 3

3*(1-(1/2)^n)/(1-(1/2))
=3*(1-(1/2)^n)/(1/2)
bring up the 2: (for x / y / z= zx / y)
=3*2(1-(1/2)^n)/1
=6*(1-(1/2)^n)

if u still dun understand, write it out for better visualisation...very simple actually