What would its volume be if the pressure were increased to 3.9 atm if the temprature did not change?
2007-04-15 16:07:35 · 3 answers · asked by scoota 1 in Science & Mathematics ➔ Chemistry
This one is Boyle's Law P1V1 =P2V2
The units are OK as is.
Just plug in and solve
2007-04-15 16:11:41 · answer #1 · answered by reb1240 7 · 0⤊ 0⤋
I know that most would think that if the pressure went up 3 times and the temperature stayed constant, then dividing the 17 by 3 would be the answer for the new volume. But in real life, I ask what gas and what temp are you starting with. For example, if propane is at 34 Degrees F at atmosphere, it would liquefy before the pressure was increased 3 times, causing the volume to change very little, while a gas like ethane would stay as a gas causing the volume to change close to 1/3rd the original.
Supercompressibility---A sample of Nitrogen and a sample of ethane have different compressibility factors. Plus, a mix of gases can cause a completely different factor. If I remember right, factors were established by lab comparison to air at 60 degrees F. , but supercompressibility factors of mixed gases has only been introduced about 1990's.
2007-04-15 16:54:26 · answer #2 · answered by Anonymous · 0⤊ 0⤋
For question variety a million, you need to use Lussac's regulation. P1/T1=P2/T2,,,,,the place P1 is the preliminary stress and T1 is the preliminary temperature. you will desire to transform your temperature this is in celsius into kelvins via including 273.sixteen to it. rearranging the equation, you will can sparkling up for P2 with.... P2 = (T1/T2)*P1
2016-10-22 06:52:34 · answer #3 · answered by pape 4 · 0⤊ 0⤋