Of two numbers, one exceeds the other by 32. Their sum is 46. Find the numbers.
The numbers are ______ and ______
All I know is how two write it out. (x+32) + x = 46
2007-04-15 15:58:04 · 7 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
Going with what you have: 2x+32=46
or 2x=14
or x=7
Therefore, your numbers are 7 and 39.
2007-04-15 16:00:32 · answer #1 · answered by bruinfan 7 · 0⤊ 1⤋
That's the way to start. Then just combine your like terms
2x + 32 = 46
subtract 32 from both sides
2x = 14
x = 7
so your first number is 7
since your second number is 32 more, it must be 39.
2007-04-15 16:01:09 · answer #2 · answered by dewkisses02 4 · 0⤊ 0⤋
from your equation you combine the x's getting 2x + 32 = 46
subtract 32 from both sides of the equaiton getting 2x = 14
divide both sides by 2 getting x = 7
there fore one of the numbers is 7 and the other is 7+32 = 39
2007-04-15 16:02:25 · answer #3 · answered by Anonymous · 0⤊ 0⤋
(x+32)+x=46 so
2x+32=46
2x=14
x=7
2007-04-15 16:01:14 · answer #4 · answered by msmthtchr 3 · 0⤊ 0⤋
7 and 39
2007-04-15 16:00:37 · answer #5 · answered by banannie3 2 · 0⤊ 1⤋
yes, then
46-32
=14
/2
=7
the two # are 7 and 39
2007-04-15 16:02:15 · answer #6 · answered by Anonymous · 0⤊ 0⤋
48
That is you had over 48 hours to do your homework, but you wait until Sunday night to do it?
2007-04-15 16:01:03 · answer #7 · answered by Postal Professor 4 · 0⤊ 0⤋