The distance of the Earth from the sun is 93 000 000 miles. If there are 3.15 × 10^7 s in one year, find the
speed of the Earth in its orbit about the sun.
2007-04-15 15:39:51 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Physics
Circumference of a circle is 2*PI*R. Earth's orbit is a circle with R = 93 million miles and PI is about 3.14. Earth covers that distance in a year. Speed is distance divided by time. Do the math.
2007-04-15 15:45:55 · answer #1 · answered by campbelp2002 7 · 0⤊ 0⤋
Rate = Distance / Time
Rate = 9.3 * 10^7 / 3.15 * 10^7
Rate - 9.3 / 3.15
Rate = 2.95 miles per second
2007-04-15 23:12:52 · answer #2 · answered by Anonymous · 0⤊ 0⤋
It is actually a simple question. You need to remember how how to find the circumference of a circle by using the radius (93,000,0000 miles).
2007-04-15 22:48:05 · answer #3 · answered by a bush family member 7 · 0⤊ 0⤋
2*Pi*r = 584336233.6
Ans/ time = 18.55 thats a miles per second.
you want meters per second huh?
well 5280 feet in mile.. = 97944 ft/s
aww boy whats the conversion from feet to meter? like .304?
I dunno using .304 you get 29774.976 m/s..
Speed of the earth = 29774.976 +/- about 200 lol
2007-04-15 23:00:11 · answer #4 · answered by TadaceAce 3 · 0⤊ 0⤋