definite integral/calculus?

Question

the value of:
⌠-2
((x-1)^2)dx
⌡0

is??

Answer 1

=1/3((x-1)^3 between 0 and -2
=1/3( -27+1) =-26/3

Answer 2

26/3, I think. Here are the steps I followed:
Multiply out (x-1)^2, rather than using substitution, and reverse the order of the limits
Then you're left with:
(using S as an integral symbol):
-S[-2 to 0] (x^2-2x+1)dx
=-(x^3/3 - 2x^2/2 + x)[-2 to 0]
=8/3+6
=26/3

Double check my math, but I think that's it! :)
Good luck.