A flower bed is to be 3m longer than it is wide. The garden will have an area of 108m^2. What will its dimensions be?
2007-04-15 14:05:40 · 6 answers · asked by Shakia O 1 in Science & Mathematics ➔ Mathematics
12m x 9m
2007-04-15 14:09:45 · answer #1 · answered by Anonymous · 1⤊ 0⤋
Let x be the width and x+3 the length.
Then the area is x(x+3) = 108
So x²+3x-108 = 0
(x+12)(x-9) = 0.
Since x must be positive, we conclude
x = 9
x + 3 = 12.
So the width is 9 and the length is 12.
2007-04-15 21:18:22 · answer #2 · answered by steiner1745 7 · 0⤊ 0⤋
width + 3 = length
length*width = 108
substituting,
(width+3)*width = 108
width^2 + 3*width - 108 = 0
use the quadratic formula to solve
-b + or - Square root of b^2 - 4ac all over 2a
(-3 + sqrt(9+432))/2 = 9
(-3 - sqrt(9+432))/2 = -12
Therefore the width can be either 9 or negative 12. However, no length can be negative!
Therefore, the width is 9 units, and the length is 12 units.
2007-04-15 21:13:37 · answer #3 · answered by Anonymous · 1⤊ 0⤋
x*(x+3) = 108, x = 9, so the width is 9m and the length is 12m.
2007-04-15 21:10:42 · answer #4 · answered by Lkk814 3 · 0⤊ 0⤋
width =9m
length=12m
2007-04-15 21:31:15 · answer #5 · answered by Dustin 1 · 0⤊ 0⤋
length= 12m
width = 9m
2007-04-15 21:12:21 · answer #6 · answered by nor_azli6 1 · 0⤊ 0⤋