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I am totally clueless on this question, please help!

In a lithium-iodine cell, Li is oxidized to Li+
I2 is reduced to 2 I-

What is the equations for the two half reactions that take place in this cell?

What is the overall reaction equation in this cell?

2007-04-15 11:51:01 · 1 answers · asked by Vienna 3 in Science & Mathematics Chemistry

1 answers

Li -----> Li+ + e-

I2 + 2e- ----> 2I-

Now multiply the first one by 2, and add them together:

2Li + I2 -----> 2LiI.

2007-04-16 06:52:12 · answer #1 · answered by Gervald F 7 · 0 0

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