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Given: A circular shaped object with an inner radius of 15 cm and an outer radius of 29 cm. There are three forces (acting perpendicular to the axis of rotation) whose magnitudes are
12 N, 24 N, and 13 N acting on the object. The force of magnitude 24 N is 25degree below horizontal.

Find the magnitude of the net torque on the wheel about the axle through the center of the object. Answer in units of Nm.

2007-04-15 11:38:37 · 2 answers · asked by p.b 1 in Science & Mathematics Physics

2 answers

The question is not clear.
Do these forces act on the inside (15 cm), outside (29 cm) or between the 15 and 29 cm. and 25degree below horizontal is not clear

T=r x F=r F sin(angle between the radius and force on the same plane)
Tnet= T1+ T2 + T3

2007-04-16 03:44:24 · answer #1 · answered by Edward 7 · 0 0

A toy Ferris Wheel undergoes an angular acceleration such that the angular speed is going from 0 to 2.fifty one rad/s in a million.35 s. anticipate that the Ferris Wheel is a around disk with radius 0.305 m and mass 7.3 kg. what's the value of the internet torque on the Wheel in N • m? angular acceleration = 2.fifty one rad/s ÷ a million.35s = a million.86 /rad/s^2 2nd of inertial of disc = ½ * mass * radius^2 = ½ * 7.3 * 0.305^2 torque = I * ? = ½ * 7.3 * 0.305^2 * a million.86 = 0.6315 N-m

2016-10-22 06:21:02 · answer #2 · answered by ? 4 · 0 0

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