2NaOH(aq) + H2SO4(aq) Na2SO4(aq) + 2H2O?

Question

12.26 mL of an aqueous sulfuric acid solution is neutralized by 26.04 mL of 0.1024 M NaOH.What is the molarity of the solution?

Answer 1

Ok

0.1024 M NaOH times 0.02604 L = 0.00267 moles

Take those Moles and divide by 12.26 mL and you get the molarity of solution

0.00267 mol / 0.01226 L = 0.2175 M or 0.22 M

Answer 2

Since H2SO4 is diprotic:

2 * moles acid = moles base
2 * Ma * Va = Mb * Vb
Ma = Mb * Vb / (2 * Va) = 0.1024 * 26.04 / 24.52 = 0.1087 M

Answer 3

the logo you have written, as such, skill 2 molecules of water, (2H2O) If the extensive type 2 have been on the right of the formulation, it would recommend hydrogen peroxyde....(H2O2) its you call now