Express sqrt _/-48 + sqrt _/25 + sqrt _/-27 in simplest a+bi form
and Solve for x: x^-3 = 27/64
2007-04-15 11:06:36 · 5 answers · asked by Anonymous in Education & Reference ➔ Homework Help
sqrt of -48 +sqrt of 25 + sqrt of -27=
sqrt of -16 sqrt of 3 +sqrt of 25 +sqrt of -9 sqrt of 3=
4i sqrt of 3 +5 +3i sqrt of 3
5+7i sqrt of 3
x^-3= 27/64
x^1/3=27/64
27x^3=64
x^3=64/27
x=4/3 4^3=64 3^3=27
2007-04-15 12:17:46 · answer #1 · answered by Dave aka Spider Monkey 7 · 0⤊ 0⤋
sqrt 48 + sqrt 25 + sqrt 27
sqrt (16 x 3) + 5 + sqrt(9x3)
4(sqrt 3) + 5 + 3(sqrt 3)
7(sqrt 3) +5
x^-3 = 27/64
1/x^3 = 27/64 Cross multiply
27 x^3 = 64
x^3 = 64/27
x = cube root of 64/27 4x4x4 = 64 3x3x3 =27
x = 4/3
2007-04-15 11:34:20 · answer #2 · answered by kale_ewart 5 · 0⤊ 0⤋
second one:
x^3=27/64
get the cubed root of each side
x=3/4
2007-04-15 11:29:12 · answer #3 · answered by Anonymous · 0⤊ 0⤋
you may desire to ISOLATE X with the intention to discover THE X fee! -2-3x=x+6 -x -x -2-4x=6 +2 +2 -4x=8 divide 4 on the two factors and x would be -2 that's easy math! how are you able to no longer understand this?!?!??! >.<
2016-11-24 20:56:24 · answer #4 · answered by ? 4 · 0⤊ 0⤋
Just add those two on each side and see if you can get the answer.
2007-04-15 11:12:29 · answer #5 · answered by DeAndre L 1 · 0⤊ 0⤋