English Deutsch Français Italiano Español Português 繁體中文 Bahasa Indonesia Tiếng Việt ภาษาไทย
All categories

(2 - 4i) - (5 + 7i)

(SQRT[x] + 3)(SQRT[x] - 3)

2x SQRT(12xy^2)] - [y SQRT(75x^3]

(2 - 3i)(4 + i)

2 / (SQRT[3] - 2)

(1 - 2i) / (-3i)

2007-04-15 10:39:37 · 2 answers · asked by K Rose 3 in Science & Mathematics Mathematics

2 answers

(2 - 4i) - (5 + 7i) =

2 - 4i - 5 - 7i =

- 3 - 11i

- - - - - - - s-

2007-04-15 11:13:41 · answer #1 · answered by SAMUEL D 7 · 0 0

(2 - 4i) - (5 + 7i)
2 - 4i - 5 - 7i
-3 - 11i

(√[x] + 3)(√[x] - 3)
Factor it! Remember, √[x] = x ^ (.5). So, x^0.5 * x^0.5 = x^1
x -3√[x] + 3√[x] -9
x - 9

(2 - 3i)(4 + i)
Factor again. i^2 = -1 because √[-1] = i. So, √[-1] * √[-1] = i^2 = -1
8 + 2i - 12i + 3
11 - 10i

2 / (√[3] - 2)
multiply both numerator & denominator by (√[3] +2) so the denominator isn't so big.
[2(√[3] +2)] / [(√[3] -2)(√[3] +2)]
[2√[3] + 4] / [3 + 2√[3] - 2√[3] -4]
[2√[3] + 4] / -1
-2√[3] - 4

(1 - 2i) / (-3i)
multiply both numerator & denominator by i since that is what makes the denominator look tough.
(i + 2) / 3

2007-04-15 18:05:40 · answer #2 · answered by flit 4 · 0 0

fedest.com, questions and answers