What is the molarity of 111 grams of KOH (formula weight = 56.1 u) in 1.25 liters of solution?
2007-04-15 10:18:48 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry
you have 111 grams KOH in 1.25 liters solution
convert the KOH to moles, since molarity is moles solute/liters solution
111 grams KOH /56.1grams/mol = 1.98 moles of KOH
1.98 moles KOH / 1.25 L solution = 1.583 M KOH solution
2007-04-15 10:23:09 · answer #1 · answered by NArchy 3 · 0⤊ 0⤋
You are 2/3 of the way there. Molarity= moles per liter. You got the moles (1.98) and the liters (1.25), so why bother us?
2007-04-15 10:23:24 · answer #2 · answered by cattbarf 7 · 0⤊ 0⤋
111/(56.1 x 1.25)
2007-04-15 10:22:09 · answer #3 · answered by Gervald F 7 · 0⤊ 0⤋
challenging factor. research from the search engines. it could help!
2014-12-08 20:08:12 · answer #4 · answered by Anonymous · 0⤊ 0⤋