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If for the reaction N2(g) + O2(g) ↔ 2NO(g), you have the initial concentration [N2] = 0.03 and [O2] = 0.08, and if Keq for the reaction at this temperature is 5.7 x 10^-7, then what are the equilibrium concentrations for N2, O2, and NO2?

2007-04-15 09:22:42 · 1 answers · asked by theweirdguy1 2 in Science & Mathematics Chemistry

1 answers

Solve ((2x) squared)/(0.03 - x)(0.08 - x) = Keq and you are well on your way!

2007-04-15 09:38:20 · answer #1 · answered by Gervald F 7 · 0 0

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