What is d/dx ln(1/x^2-1)=?

2007-04-15 08:07:40 · 2 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics

the derivative of ln u = u' / u (easy, right?!).

[-2x (x² - 1)^-2] / [(x²-1)^-1]

= -2x / (x² -1)

2007-04-15 08:29:10 · answer #1 · answered by Kathleen K 7 · 0⤊ 0⤋

Use the chain rule to get 2x/(xÂ²-1).

2007-04-15 15:16:42 · answer #2 · answered by steiner1745 7 · 0⤊ 1⤋

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