ap calclulus is super hard?

Question

if lim x -> 2 [ln f (x)] = 1 then lim x-> 2 f(x) =

Answer 1

exp(1) = e

Answer 2

i might say that AP Calculus is a reasonably super direction load, in case you took precalc its probable slightly extra desirable than that. relatively relies upon on how sturdy the instructor is tho. I took AP Calc with a brilliant highschool instructor, have been given an A, then Calc in college and have been given a D first time around, so it relatively does count. determine you have a sturdy calculator and are prepared to do the homework and you will do super.

Answer 3

That's very easy.
If ln[f(x)] = 1 as x goes to 2,
then f(x) = e^1 as x goes to 2.

f(x) = e = 2.718

Answer 4

since we are intereted in liit of f(x) and the lim of ln f(x) = 1, then the lim of f(x) would be e.

Answer 5

ln (f(2))=1
f(2)=?
base e
power=1

e^1=f(2)

f(2)=e

answer: e

Answer 6

e