This is a codominant trait.
If SS = sickle cell anemia
SN = trait
NN = normal
Then two parents that are SN x SN have a 1/4 chance of having a child with sickle cell anemia, as well as 1/4 chance of NN normal, and 1/2 chance of SN trait.
2007-04-15 06:57:27
·
answer #1
·
answered by ecolink 7
·
1⤊
0⤋
I'm assuming that when you say "sickle-cell trait" you mean that both of them carry the gene for sickle-cell anemia, but neither actually has the disease. In other words, they're both heterozygous for that gene, with one normal gene and one sickle-cell gene.
For a child to have sickle-cell anemia, he/she would have to have two sickle-cell genes. The odds of the mother passing down a sickle-cell gene are 1/2, and the odds for the father are the same. So the odds of BOTH of them passing down the gene are 1/2 * 1/2, or 1/4. There's a 1-in-4 probability that any given child will have sickle-cell anemia.
If you want to know the odds that ANY of their children will have it, you'll first have to say how many kids they have.
2007-04-15 07:00:11
·
answer #2
·
answered by Amy F 5
·
0⤊
0⤋
If you use the box method it is 75% that the children will inherit and 25% that the children will NOT inherit the sickle-cell trait.
2007-04-15 06:59:00
·
answer #3
·
answered by mirandanicole 1
·
1⤊
1⤋
it relatively is a false impression that sickle cellular trait agencies won't be able to have issues. They commonly stay a typical life, yet approximately 5% might have indications fairly with rigidity, disease, or modifications in altitude
2016-10-03 00:51:54
·
answer #4
·
answered by ? 4
·
0⤊
0⤋
It depends if the trait is recessive or dominant if it recessive the children might have it but if its dominant it is almost a certainty
2007-04-15 07:52:12
·
answer #5
·
answered by Gabriel l 2
·
0⤊
0⤋
it is very likely that your children will inherit the trait
2007-04-15 07:00:23
·
answer #6
·
answered by Anonymous
·
0⤊
1⤋
25%.
2007-04-15 13:02:20
·
answer #7
·
answered by felipelotas1 3
·
0⤊
0⤋